Solve for x 2√3x^25x√3=0 Get the answers you need, now! Best answer 2√3x2 ˗ 5x √3 ⇒ 2√3x2 ˗ 2x ˗ 3x √3 ⇒ 2x (√3x ˗ 1) ˗ √3 (√3x ˗ 1) = 0 ⇒ (√3x ˗ 1) or (2x − √3) = 0 ⇒ (√3x ˗ 1) = 0 or (2x − √3) = 0 ⇒ x = 1 3 or x = 3 2 ⇒ x = 1 3 x 3 3 = 3 3 or x = 3 2The given equations is 2√3x 2 5x √3 = 0 Comparing it with ax 2 bx c = 0we get a = 2√3, b = 5 and c = √3 ∴ Discriminant, D = b 2 4ac = (5) 2 4 x 2√3 x √3 = 25 25 = 1 > 0 So, the given equation has real roots Now, √D = √1 = 1 Hence, √3/2 and
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