[最も好ましい] y''(x^2 1)=2xy' 138991-Dy/dx=x^2+y^2+1/2xy

1 solution(s) foundx^22xyy^21 x^22xyy^21 See steps Step by Step Solution Step 1 Step 2 Pulling out like terms 21 Pull out like factors x 2 2xy y 2 1 = 1 • (x 2 2xy y 2 1) Final result x 2 2xy y 2 1 Why learn thisExactdifferentialequationcalculator 2xy^24=2(3x^2y)y', y(1)=8 en Related Symbolab blog posts Advanced Math Solutions – Ordinary Differential Equations Calculator, Bernoulli ODE Last post, we learned about separable differential equationsTranscribed image text Solve the Legendre equation (1 x^2)y" 2xy' n(n 1) y = 0 by direct series substitution (a) Verify that the indicial equation is k(k 1) = 0 (b) Using k = 0, obtain a series of even powers of x (a_1 = 0) y_even = a_0 1 n(n 1)/2!

Consider The Graph Of X 2 Xy Y 2 1 A Find An Chegg Com

Dy/dx=x^2+y^2+1/2xy

【人気ダウンロード！】 2√3x^2-5x √3=0 338499-(x+3)(3x-2)(5x+8)^2 0

 Solve for x 2√3x^25x√3=0 Get the answers you need, now! Best answer 2√3x2 ˗ 5x √3 ⇒ 2√3x2 ˗ 2x ˗ 3x √3 ⇒ 2x (√3x ˗ 1) ˗ √3 (√3x ˗ 1) = 0 ⇒ (√3x ˗ 1) or (2x − √3) = 0 ⇒ (√3x ˗ 1) = 0 or (2x − √3) = 0 ⇒ x = 1 3 or x = 3 2 ⇒ x = 1 3 x 3 3 = 3 3 or x = 3 2The given equations is 2√3x 2 5x √3 = 0 Comparing it with ax 2 bx c = 0we get a = 2√3, b = 5 and c = √3 ∴ Discriminant, D = b 2 4ac = (5) 2 4 x 2√3 x √3 = 25 25 = 1 > 0 So, the given equation has real roots Now, √D = √1 = 1 Hence, √3/2 and

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(x+3)(3x-2)(5x+8)^2 0